Epoch

You are given a string representing an attendance record for a student. The record only contains the following three characters:

1. 'A' : Absent.
2. 'L' : Late.
3. 'P' : Present.

A student could be rewarded if his attendance record doesn't contain more than one 'A' (absent) or more than two continuous 'L' (late).

You need to return whether the student could be rewarded according to his attendance record.

Example 1:

Input: "PPALLP"
Output: True

Example 2:

Input: "PPALLL"
Output: False

想法

連續超過兩次 L 或者擁有兩次A 就回傳 0

code

bool checkRecord(char* s) {
    char tmp = ' ';
    int late = 0;
    int absent = 0;
    int late_status = 0;
    while (*s) {
        if (tmp == *s && tmp == 'L') {
            late++;
            if (late == 2) 
                late_status = 1;
        } else {
            late=0;
        }
        if (*s == 'A') {
            absent++;
        }
        tmp = *s;
        s++;
    }
    if (absent >= 2 || late_status == 1) {
        return 0;
    }
    else 
        return 1;
}